the sum of the three number in ap is 24 and their product is 242 find the numbers
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Step-by-step explanation:
Let the three terms are in an A.P. are a-d, a , a+d
Sum is given 24
(a-d)+ a + (a+d)=24
3a=24
a=24/3
a=8
Product is given 242
(a-d) (a) (a+d)=242
Put a= 8
(8-d) (8) (8+d)=242
(8-d) (8+d) =242/8
64 + 8d -8d- d^2=121/4
64 -d^2=121/4
Taking square root both the sides
8 - d = 11/2
-d= 11/2 -8
-d= -5/2
d=5/2
Put a and d in three terms
a-d=8-5/2=11/2
a=8
a+d=8+5=13
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