the sum of the three number in AP is 27 the product of frist and last 56 find the number
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Answer:
S³=27
a×l =56
S³=N/2(A+l)
27=n/2(56/l+l)
27 =n/2(56+l²)
27×2=n
56+l²
27= n
28+l²
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