the sum of the three numbers in a.p is 12 and sum of their cubes is 288.
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let the no. be a,a+d,a-d.
a+a+d+a-d=12
3a=12
a=12/3
a=4
a^3+a+d^3+a-d^3=288
put the formula of a+b^3$a+b^3 and put the value of a $d then come ur answer.
a+a+d+a-d=12
3a=12
a=12/3
a=4
a^3+a+d^3+a-d^3=288
put the formula of a+b^3$a+b^3 and put the value of a $d then come ur answer.
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