the sum of the three terms in AP is -3 and their is 8. find the numbers
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Let second number be a .
Therefore other two numbers are a-d and a+d .
Therefore ---
a - d + a + a + d = -3
3a = -3
a = -1
Therefore -----
( a - d ) ( a ) ( a + d ) = 8
( a² - d² ) ( a ) = 8
( a² - d² ) ( -1 ) = 8
a² - d² = -8
1 - d² = -8
:. d² = 9
.: d = 3
So the numbers are : -4 , -1 , 2 .
HOPE IT IS MOST HELPFUL!!!!!!!!!!
Therefore other two numbers are a-d and a+d .
Therefore ---
a - d + a + a + d = -3
3a = -3
a = -1
Therefore -----
( a - d ) ( a ) ( a + d ) = 8
( a² - d² ) ( a ) = 8
( a² - d² ) ( -1 ) = 8
a² - d² = -8
1 - d² = -8
:. d² = 9
.: d = 3
So the numbers are : -4 , -1 , 2 .
HOPE IT IS MOST HELPFUL!!!!!!!!!!
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