Question

the sum of the three terms which are in an arithmetic progressions is 33.if the product of the first and third term exceeds the second term by 29 find the arithmetic progression​

Answer 1

Answer:

2,11,20

Explanation:

let our arithmetic progression be a-d,a,a+d with common difference d

so sum is a-d+a+a+d=33

3a=33

a=11

now (a-d)(a+d)=a+29

a²-d²=a+29

we have a=11

so 121-d²=40

d²=81

d=9