the sum of the two angles is 80 and their difference is 20 find all the angles
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Answer:
Consider a △ABC,
then according to the given condition we have:
∠A+∠B=80
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and ∠A−∠B=20
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⇒2∠A=100
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⇒∠A=50
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⇒∠B=30
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Using the sum of all the angles of the triangle is 180
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We have: ∠A+∠B+∠C=180
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⇒50
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+30
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+∠C=180
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⇒∠C=100
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Hence ∠A=50
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, ∠B=30
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and ∠C=100
o
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