Question

The sum of the two-digit number and the number obtained by interchanging the digits is 132. The digit in the ten’s place is 2 more than the digit in the unit’s place. Complete the activity to find the original number. Activity: Let the digit in the unit’s place is y and the digit in the ten’s place is 푥. ∴ The number = 10 푥 + 푦 ∴ The number obtained by interchanging the digits = ∴ The sum of the number and the number obtained by interchanging the digits = 132 ∴ 10 푥 + 푦 + 10 푦 + 푥 = ∴ x + y = (I) , By second condition, Digit in the ten’s place = digit in the unit’s place + 2 ∴ x - y = 2 . . . (II) Solving equation (I) and (II) ∴ x = y = Ans: The original number =​

Answer 1

Answer:

The original number=75

Step-by-step explanation:

Let the unit digit=x

then digit at 10's place=x+2

Then original number N =10*(x+2)+x

=10x+20+x

N=11x+20

Number formed after interchanging the digits

N'=10x+x+2=11x+2

Given that

N+N'=132

11x+20+11x+2=132

22x=132-22=110

x=110/22=5

Thus unit digit of original number=5

Digit at 10's place=5+2=7

Thus the original number=75

Answer 2

Answer:

Original number =10x+y

=10(7)+5

=75