Question

The sum of the two-digit number and the number obtained by interchanging the digits is 132. The digit in the ten’s place is 2 more than the digit in the unit’s place. Complete the activity to find the original numb​

Answer 1

Answer:

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Step-by-step explanation:

so let the required two digit number be 10x+y

wherein digit at tens place is x and that of units place is y

so number obtained by reversing digits=10y+x

so according to first condition

10x+y+10y+x=132

ie 11x++11y=132

so x+y=12 (1)

according to the second condition

x=y+2 (1)

substitute value of x in (2) from (1)

we get y+y+2=12

ie 2y=10

so thus y=5

substitute value of y in (1)

we get x=7

so our required two digit number=10x+y

=(10×7)+5

=70+5

=75

hence required two digit number is 75