the sum of the two digit number and the number of its digits is 110 if 10 is subtracted from the original number then the new number is 3 more than 5 times the sum of its digit of the original number and the number
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Original number = (10x+y)
Let the digits be x and y
The no is 10x+y
After interchanging the digits
New number = (10y+x)
(10x+y) + (10y+x) = 110
11x +11y = 110
11(x+y)= 110
x+y = 110/11
x+y= 10 ¹
x= 10-y ²
(10x+y) - 10 = 4+ 5(x+y)
(10x+y) - 10 = 4+ 5(10)
(10x+y) = 4+ 50+10
(10x+y) = 64
10(10-y) +y = 64
100-10y +y= 64
100 -9y = 64
-9y = 64-100
-9y = -36
y= 36/9= 4
y= 4
putting the value of y in eqn 2
x= 10-y
x= 10-4
x= 6
Hence , the first number is 6 & second number is 4.
The no is 64
sharanrao38:
ok sorry
Bro I will do it again
Donot worry some problem is there
Some problem in question bro such a number is not possible
Instead of 3 there should be 4
ok bro thank you for your answer
I may have wrote the question wrongly
I'll copy your answer
Can you please mark as brainliest
You can but there is a error in your question brother instead 3 more than 5 it should be 4 more than 5
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