Question

the sum of the two digit number and the obtained reverse number is 88. if the difference of digit at the ten's place and that at unit's place is 6.find the digit at the ten's place of number.
​

Answer 1

Answer:

7

Step-by-step explanation:

let the number's ten's digit be x and unit digit be y

hence, the number will be = 10x+y

with the digits reversed,

the new number=10y+x

as given,

10x+y+10y+x=88

11x+11y=88

if we divide 11 from both sides, and cancel it, then, we have

x+y=8>(1)

and, as given,

x-y=6>(2)

subtracting (2) from (1), we have,

2y=2

y=1

putting in the value of y in (1)

x+y=8

x+1=8

x=7

hence, the number is 7