Question

the sum of the two digit number is 10 .the number obtained by interchanging the digits exceeds the original by 36. find the original number

Answer 1

let xy be the two digit number .
therefore , it is of  the form 10x+y.
GIVEN,10x+y=10 ...........(1)
 from 1,x=10-y/10......(2)
the number obtained by reversing the order of digits is yx=10y+x
given.10y+x=10x+y+36.
when you solve these equations,you get x=23,y=-13
(verification:x+y=10 (given)
23+(-13)=10 
10=10)

Answer 2

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