The sum of the two digit number is 12. If the number formed by reversing its digits is greater than the original number by 18,find the original number...
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Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝
Let to be 1 unit digit number y
then
let to be 10unit digit number x
then
x+y=12
Again
10x+y+18=10y+x
10x-x+y-10y=-18
9x-9x=-18
9(x-y)=-17
x-y=-2
Solving the equation for elimination method
x+y=12
x-y=-2
______
2y=14
y=14/2=7
then,
x+y=12
x+7=12
x=12-7
x=5
then,
Original Number=10x+y
10*5+7
50+7
57
that's all
@Sujeet yaduvanshi
Let to be 1 unit digit number y
then
let to be 10unit digit number x
then
x+y=12
Again
10x+y+18=10y+x
10x-x+y-10y=-18
9x-9x=-18
9(x-y)=-17
x-y=-2
Solving the equation for elimination method
x+y=12
x-y=-2
______
2y=14
y=14/2=7
then,
x+y=12
x+7=12
x=12-7
x=5
then,
Original Number=10x+y
10*5+7
50+7
57
that's all
@Sujeet yaduvanshi
AntarikshSharma102:
;-)
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