The sum of the two digit number is 12. the number obtained by reversing the digits is 36 greater than the original number . find the number
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Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number = 10y + x
Given:
x + y = 12
y = 12 – x -----------1
Also given:
10y + x - 10x – y = 18
9y – 9x = 18
y – x = 2 -------------2
Substitute the value of y from eqn 1 in eqn 2
12 – x – x = 2
12 – 2x = 2
2x = 10
x = 5
Therefore, y = 12 – x = 12 – 5 = 7
Therefore, the two-digit number is 10x + y = (10*5) + 7 = 57
Anonymous:
i got it
48
ok
Let number is xy , then two digits is x,y
x+y=12,(1)
Number xy can be written as 10x+y
On reversing number
10y+x=10x+y+36
9(y-x)=36
y-x=4 (2)
Add (1)+(2)
2y=16,y=8
x=4
Number is 48
x+y=12,(1)
Number xy can be written as 10x+y
On reversing number
10y+x=10x+y+36
9(y-x)=36
y-x=4 (2)
Add (1)+(2)
2y=16,y=8
x=4
Number is 48
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