Question

the sum of the two digit number is 12 the number of obtained by interchanging the two digits exceeds the given number by 18 find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be 'x' and 'y' with x being the unit digit:

x+y= 12

Therefore, y= 12-x

Number= 10y+x

             = 10(12-x)+x

             = 10×12-10x + x

             = 120-9x

Orginal Number= 120-9x

Reversed Number= 10x+(12-x)

                              = 10x-x+12

                              = 9x+12

Reversed Number= 9x+12

120-9x+18=9x+12 (as written in the question, the reversed no. exceeds orginal no. by 18)

120-9x+18= 9x+12

=120+18-9x=9x+12

=138-9x=9x+12

Now, that we got it simplified, lets continue with transposition method:

138-12-9x= 9x

=126-9x=9x

126=9x+9x

=126=18x

$\frac{18x}{18}$=$\frac{126}{18}$

∴x= 126÷18= 7

Unit digit= 7

x+y= 12

7+y=12

12-7=y

=5

Tens digit=5

∴Orginal Number=57

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Thats it!

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Answer 2

ANSWER:

may this picture will help you.

thank you☺️