the sum of the two digit of a 2-digit number is 13 if 9 is subtracted from the number the digits are reversed what is the number
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Answer:
76
Step-by-step explanation:
let two digits of a number be x and y
x+y = 13. ----->1
since X is in tens place,
10x+y will be the number
10x+y-9=10y+x
10x-x+y-10y=9
9x-9y=9
9(x-y)=9
x-y = 9/9
x-y = 1. ------->2
subtract eq 1-2
2y = 12
y = 12/2
y = 6
substitute in 1
x+6 = 13
x = 13-6
x = 7
the number is ,
10x+y = 10(7)+6 = 70+6 = 76
reverse number is ,
10y+x = 10(6)+7 = 60+7 = 67
Verification
76-9 = 67
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Answer:
I don't understand question
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