Math, asked by narayanarvindpatil, 3 months ago

the sum of the two digit of a 2-digit number is 13 if 9 is subtracted from the number the digits are reversed what is the number
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Answers

Answered by krishnas10
0

Answer:

76

Step-by-step explanation:

let two digits of a number be x and y

x+y = 13. ----->1

since X is in tens place,

10x+y will be the number

10x+y-9=10y+x

10x-x+y-10y=9

9x-9y=9

9(x-y)=9

x-y = 9/9

x-y = 1. ------->2

subtract eq 1-2

2y = 12

y = 12/2

y = 6

substitute in 1

x+6 = 13

x = 13-6

x = 7

the number is ,

10x+y = 10(7)+6 = 70+6 = 76

reverse number is ,

10y+x = 10(6)+7 = 60+7 = 67

Verification

76-9 = 67

Answered by sheetalladdha
0

Answer:

I don't understand question

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