Question

The sum of the two digits number is 15. If the new number formed by reversing the digits is less than the original number by 27 find the original two digit number

Answer 1

Step-by-step explanation:

let the tens digit be ' a ' and the ones digit be 'b'

a + b = 15 ( given ) - A

(10*a + b ) - 27 = 10*b + a

implies,

9a - 9b = 27. - B

by 9A + B we get

18a = 135 + 27

so we get,

a = 9

b = 6

so the numbers are 96 and 69

Answer 2

Step-by-step explanation:

150-9x

let the one's figure be x

then ten's digit is 15-x.

therefore the no. is

10(15-x)+x

= 150-10x+x=150-9x

after digits are inversed the no. is

10(x)+15-x=10x+15-x=9x+15

the equation is

150-9x=9x+15+27

150-9x=9x+42

150=18x+42

150-42=18x

108=18x

x=108/18=6

one's digit is 6 then 10's digit is 15-6=9

therefore the original no. is 96.

reversed no. is 96-27=69