Question

the sum of the two digits number is 15. If the number formed by reversing the digits is less than the original number by 27 find the original number

Answer 1

let tens digit of the original number be x

so original number,

10(x) + (15-x) 

reversing digits mean

10(15-x) + x

therefore

[10(x) + (15-x)]-[10(15-x)+x] = 27

or  10x + 15-x - 150+10x-x = 27

or 10x + 10x + 15 - 150 -x - x = 27

or 20x - 135 -2x = 27

or 18x - 135 = 27

or 18x = 27 + 135

or 18x = 162

or x = 162/18

or x = 9

original number = 10(x) + (15-x) 

                              = 10(9) + (15-9)

                              = 90+6

                              = 96

 

Answer 2

Answer:

96

Step-by-step explanation:

Hi guys here is a detailed explanation for the above question

Now, I think most of you notice that if the sum of the digits is 15, we can let the unknown digits be x and (15-x), If you work it out you find that the sum of x and (15-x) is nothing but 15

Now, how are you going to put these variables in the format of a number??

What we are going to do is multiply the digit in the tens place ( that is x ) by 10 ( obviously ) !!

So, we can write the number like this. 10 ( x ) + ( 15- x )

And if you reverse the order of the digits, you put ( 15- x ) in the tens place and now multiply THAT by 10

So, we can write the number like this. 10 ( 15 - x ) + x

Just to recall the original number is....10(x) + ( 15-x )

and the new number is...........10( 15-x ) + x

So, I believe that now most of you can make an equation to the question and if not.

KEEP SCROLLING

10(x) + (15-x) = 10( 15 - x ) + x + 27

10x + 15 - x = 150 - 10x + x + 27

9x + 15 = 150 - 9x + 27

18x = 150 + 27 - 15 = 162

Therefore x = __162__ = 9

18

I really hope this answer helps all of you