The sum of the two digits number is 9. The number is 6 times the unit digit. Find the number.
Answers
Answered by
0
Let two numbers be X and Y
then according to given condition X+Y=9
the number is six times the unit digit:Y>6
therefore Y can be three numbers either 7,8,9
and X will be 2,1,0
hope it helps
then according to given condition X+Y=9
the number is six times the unit digit:Y>6
therefore Y can be three numbers either 7,8,9
and X will be 2,1,0
hope it helps
NikhilSom:
thanks for help but it is not right
Answered by
1
Hi ,
Let
Ten's place digit = x
Units place digit = ( 9 - x )
The number = 10x + 9 - x
= 9x + 9 ----( 1 )
According to the problem given ,
9x + 9 = 6 ( 9 - x )
9x + 9 = 54 - 6x
9x + 6x = 54 - 9
15x = 45
x = 45/15
x = 3
Therefore ,
Required number = 9x+ 9
= 9 × 3 + 9
= 27 + 9
= 36
I hope this helps you.
: )
Let
Ten's place digit = x
Units place digit = ( 9 - x )
The number = 10x + 9 - x
= 9x + 9 ----( 1 )
According to the problem given ,
9x + 9 = 6 ( 9 - x )
9x + 9 = 54 - 6x
9x + 6x = 54 - 9
15x = 45
x = 45/15
x = 3
Therefore ,
Required number = 9x+ 9
= 9 × 3 + 9
= 27 + 9
= 36
I hope this helps you.
: )
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