The sum of the two digits of a number is 8. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number ?
Answers
Answered by
0
▶ Question - The sum of the two digits of a number is 8. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number.
▶ Explanation :-
Given sum of the two digits of a numbers is 8
Let the unit digit be y and tens digit be x
∴ x + y = 8 ------- ( 1 )
Let the number be 10x + y
Given the number is subtracted from the number obtained by reversing its digits, the result is 54
∴ Reversed number = 10y + x
According to the Question :-
=> 10y + x - ( 10x + y ) = 54
=> 10y + x - 10x - y = 54
=> 9y - 9x = 54
=> 9 ( y - x ) = 54
=> y - x = 6
=> x - y = - 6
=> x = - 6 + y
Substituting value of x in equation ( 1 ) we get :-
=> x + y = 8
=> - 6 + y + y = 8
=> - 6 + 2y = 8
=> 2y = 8 + 6
=> 2y = 14
=> y = 14 / 2
=> y = 7
Substituting value of y in equation ( 1 ) we get :-
=> x + y = 8
=> x + 7 = 8
=> x = 8 - 7
=> x = 1
∴ Original Number = 10x + y
= 10 × 1 + 7
= 10 + 7
= 17
∴ Reversed number = 10y + x
= 10 × 7 + 1
= 70 + 1
= 71
Answered by
0
_________Heyy Buddy ❤________
______Here's your Answer ____________
Given;
sum of the two digits of a numbers is 8
Let the unit digit be y and tens digit be x
∴ x + y = 8 ------- ( 1 )
Let the number be 10x + y
Given;
The number is subtracted from the number obtained by reversing its digits, the result is 54
∴ Reversed number = 10y + x
A.T.Q.
=> 10y + x - ( 10x + y ) = 54
=> 10y + x - 10x - y = 54
=> 9y - 9x = 54
=> 9 ( y - x ) = 54
=> y - x = 6
=> x - y = - 6
=> x = - 6 + y
Putting x = (-6 + y) in equation ( 1 ). we get,
=> x + y = 8
=> - 6 + y + y = 8
=> - 6 + 2y = 8
=> 2y = 8 + 6
=> 2y = 14
=> y = 14 / 2
=> y = 7
Putting y = 7 in equation (1) we get :-
=> x + y = 8
=> x + 7 = 8
=> x = 8 - 7
=> x = 1
∴ Original Number = 10x + y
= 10 × 1 + 7
= 10 + 7
= 17
∴ Reversed number = 10y + x
= 10 × 7 + 1
= 70 + 1
= 71.
✔✔✔
______Here's your Answer ____________
Given;
sum of the two digits of a numbers is 8
Let the unit digit be y and tens digit be x
∴ x + y = 8 ------- ( 1 )
Let the number be 10x + y
Given;
The number is subtracted from the number obtained by reversing its digits, the result is 54
∴ Reversed number = 10y + x
A.T.Q.
=> 10y + x - ( 10x + y ) = 54
=> 10y + x - 10x - y = 54
=> 9y - 9x = 54
=> 9 ( y - x ) = 54
=> y - x = 6
=> x - y = - 6
=> x = - 6 + y
Putting x = (-6 + y) in equation ( 1 ). we get,
=> x + y = 8
=> - 6 + y + y = 8
=> - 6 + 2y = 8
=> 2y = 8 + 6
=> 2y = 14
=> y = 14 / 2
=> y = 7
Putting y = 7 in equation (1) we get :-
=> x + y = 8
=> x + 7 = 8
=> x = 8 - 7
=> x = 1
∴ Original Number = 10x + y
= 10 × 1 + 7
= 10 + 7
= 17
∴ Reversed number = 10y + x
= 10 × 7 + 1
= 70 + 1
= 71.
✔✔✔
Similar questions
Chemistry,
7 months ago
Social Sciences,
7 months ago
Biology,
1 year ago
Math,
1 year ago
Math,
1 year ago