Question

The sum of the two digits of a two digit no is 15 and the difference between the two digits of tge two digit number is 3 .what is the product of the two digits of the two digit number?

Answer 1

Let the two digits be x and y respectively.

Then,

➡ x + y = 15. ............. (1)
➡ x - y = 3.. .............(2)
-----------------
➡ 2x = 18

➡ x = 18/2 = 9

Putting the value of x in eq (1),

➡ x +y = 15

➡ 9 + y = 15

➡ y = 15 - 9 = 6.

So,

x = 9 and y = 6

Now,

Product of the digits = 9× 6 = 54.

Required answer is 54.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\:\:$

$\green{\underline \bold{Given :}}$

$\:\:$

• The sum of the two digits of a two digit no is 15

$\:\:$

• Difference between the two digits of the two digit number is 3

$\:\:$

$\red{\underline \bold{To \: Find:}}$

$\:\:$

• Product of the two digits of the two digit number

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

Let the tens digit be 'x'

Let the ones digit be 'y'

$\:\:$

$\purple{\underline \bold{According \: to \: the \ question :}}$

$\:\:$

$\purple\longrightarrow$ $\sf x + y = 15$ -------(1)

$\:\:$

Also,

$\:\:$

$\purple\longrightarrow$ $\sf x - y = 3$ -------(2)

$\:\:$

$\underline{\bold{\texttt{Adding (1) And (2)}}}$

$\:\:$

$\sf \longmapsto x + y + x - y = 3 + 15$

$\:\:$

$\sf \longmapsto 2x = 18$

$\:\:$

$\sf \longmapsto x = \dfrac { 18 } { 2 }$

$\:\:$

$\bf \dashrightarrow x = 9$

$\:\:$

$\underline{\bold{\texttt{Putting x = 9 in (1)}}}$

$\:\:$

$\sf \longmapsto 9 + y = 15$

$\:\:$

$\bf \dashrightarrow y = 6$

$\:\:$

$\underline{\bold{\texttt{Product of digits :}}}$

$\:\:$

$\purple\longrightarrow$ $\sf 9 \times 6$

$\:\:$

$\red{\bold{Product \: of \: digits \: = \: 54 \: }}$

$\rule{200}5$