Question

The sum of the two digits of a two digit number is 12 , If the decreased by 10 ,

Its’ digits get reversed, The number is ,​

Answer 1

Answer:

57

Step-by-step explanation:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x=5

Hence, the required number is 57.

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