The sum of the two digits of a two digit number is 9. if 63 is subtracted from the number , its digit are reversed. find the number
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Answered by
4
Let us assume, x and y are the two digits of a two-digit number
Therefore, The number = 10x + y and reversed number = 10y + x
Given:
x + y = 9 ---------------1
Also given:
10x + y - 63 = 10y + x
9x - 9y = 63
x - y = 7 -----------------2
Adding equation 1 and equation 2
2x = 16
x = 8
Therefore, y = 9 - x = 9 - 8 = 1
Therefore, The two digit number = 10x + y = 10*8 + 1 = 81
Therefore, The number = 10x + y and reversed number = 10y + x
Given:
x + y = 9 ---------------1
Also given:
10x + y - 63 = 10y + x
9x - 9y = 63
x - y = 7 -----------------2
Adding equation 1 and equation 2
2x = 16
x = 8
Therefore, y = 9 - x = 9 - 8 = 1
Therefore, The two digit number = 10x + y = 10*8 + 1 = 81
Answered by
3
Let p be the product and n be the number.
Product × Number = 18 Equation - (1)
Adding values of p for Equation - (1)
n² + 7n = 18
n² + 7n - 18 = 0
n² + 9n - 2n - 18 = 0
This negative values is not correct so,
2 = number
7 + 2 = 9 is the product
Therefore, product = 9
The Number =
Therefore, 92 is the two digit number
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