The sum of the two digits of a two digits number is 9.if 63 is subtracted from the number it's digits are reversed. find the number
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Answered by
4
Answer:
Step-by-step explanation:
Let the ten's digit be x. Then, unit's digit = (9 - x).
Number = l0x + (9 - x) = 9x + 9.
Number obtained by reversing the digits = 10 (9 - x) + x = 90 - 9x.
therefore, (9x + 9) - 63 = 90 - 9x
=>18x = 144
=>x = 8.
So, ten's digit = 8 and unit's digit = 1.
Hence, the required number is 81.
Answered by
3
Answer:
The answer would be 81.
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