Question

The sum of the two number is 39. If first number is twice the second number then find the number ​

Answer 1

Answer:

Here's what we know:

a + b = 39 (the sum of two numbers is 39)

2a + 3b = 101 (2 times the first plus 3 times the second is 101)

Let's solve through substitution. Let's isolate a:

a = 39 - b

Plug in the value:

2(39 - b) +3b = 101

78 -2b + 3b = 101

78 + b = 101

Subtract 78:

b = 23

a = 39 - 23

a = 16

Check:

2 * 16 + 3 * 23 = 101

32 + 69 = 101

101 = 101

Answer 2

Answer:

Let the first number be X and the second number be y.So, 2x+3y=36 (equation 1)3x+2y=39 (equation 2)Adding both the equations, 5x+5y=75Or X+y=15 (equation 3)Now eqn 2 - eqn 1 is x-y=3 (equation 4)Now, solving for X, adding equation 3 and 4, 2x=18 or X=9So, y =x-3 = 9–3=6So the smaller number is 6.

Step-by-step explanation:

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