The sum of the two numbers is 29, and the greater number is 4 less than twice the lesser number
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x+y=29
x=2y-4
so substuting x as above eqn
2y-4+y=29
3y=29+4
y=33/3=11
x=29-11
x=18
Therefore two numbers are 18 and 11
x=2y-4
so substuting x as above eqn
2y-4+y=29
3y=29+4
y=33/3=11
x=29-11
x=18
Therefore two numbers are 18 and 11
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Answer:
i have no idea lmao
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