The sum of the two numbers is 35 and their product is 250.what is the sum of the reciprocals of these numbers.
Answers
Answered by
5
a+b=35
ab=250
a=250/b
250/b+b=35
250+b2/b=35
b2-35b+250=0
b2-25b-10b+250=0
b(b-25)-10(b-25)=0
(b-25)(b-10)=0
b=25,10
let b=10
a+10=35
a=25.
sum of their reciprocal=1/25+1/10
=35/250
=7/50
therefore sum of there reciprocals=7/50
ab=250
a=250/b
250/b+b=35
250+b2/b=35
b2-35b+250=0
b2-25b-10b+250=0
b(b-25)-10(b-25)=0
(b-25)(b-10)=0
b=25,10
let b=10
a+10=35
a=25.
sum of their reciprocal=1/25+1/10
=35/250
=7/50
therefore sum of there reciprocals=7/50
Yuv15:
correct answer
please give me brain liest answer pleaseeee
Answered by
0
Answer:
a+b=35
ab=250
a=250/b
250/b+b=35
250+b2/b=35
b2-35b+250=0
b2-25b-10b+250=0
b(b-25)-10(b-25)=0
(b-25)(b-10)=0
b=25,10
let b=10
a+10=35
a=25.
sum of their reciprocal=1/25+1/10
=35/250
=7/50
therefore sum of there reciprocals=7/50
Step-by-step explanation:
Similar questions