The sum of the two opposite angles of a parallelogram is 150° .Find the measure of any one of the other two angles.
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Answered by
40
we know that opposite angles of parallelogram are equal
let angle D of parallelogram be x
other angle B = x
and according to question ,
angle A + angle C = 150°
=> sum of all angles of quadrilaterals is 360°
angle A + angle C+ angle B + angle D = 360°
=> 150°+x+x = 360°
=> 2x = 360-150 => 210°
x = 210/2 = 105°
hope this helps
let angle D of parallelogram be x
other angle B = x
and according to question ,
angle A + angle C = 150°
=> sum of all angles of quadrilaterals is 360°
angle A + angle C+ angle B + angle D = 360°
=> 150°+x+x = 360°
=> 2x = 360-150 => 210°
x = 210/2 = 105°
hope this helps
Sneha3123:
nice answer
Answered by
0
Step-by-step explanation:
Remaining =360°-15O°
=210°
two angles =210°/2
=105°
one angle =105°
and other angle =105°
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