The
sum of the two positive integers multiplied by the bigger number is 204, and
their difference multiplied by the smaller number is 35. The numbers are ?
Answers
Answered by
10
let
a,b be the integers.
and a is the bigger integer and b is the smaller integer.
as per given data,
(a+b)a=204
=>a^2+ab=204 -(1)
and (a-b)b=35
=>ab-b^2=35 -(2)
solving 1 and 2,we get a^2+b^2=169
=>so here a^2=144,b^2=25
=>a=12 and b=5
so,the numbers are 12 and 5.
a,b be the integers.
and a is the bigger integer and b is the smaller integer.
as per given data,
(a+b)a=204
=>a^2+ab=204 -(1)
and (a-b)b=35
=>ab-b^2=35 -(2)
solving 1 and 2,we get a^2+b^2=169
=>so here a^2=144,b^2=25
=>a=12 and b=5
so,the numbers are 12 and 5.
ashimgolder:
a^2=144 ,b^=25 how calculate it?
Answered by
1
let the numbers be a and b with a>b. therefore a(a+b)=204 and b(a-b)=35.
subtracting we get a^2+b^2=169. now we know that since a,b are positive integers a≠0 and b≠0. therefore a=12, b=5.
subtracting we get a^2+b^2=169. now we know that since a,b are positive integers a≠0 and b≠0. therefore a=12, b=5.
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