Question

The sum of the weights of an iron piece and a copper piece is 1280g.The volume of copper piece is twice that of the iron piece.If the weight of 1 cu.cm of iron is 7.8 g and that of copper is 8.9 g,find the volume of each piece.​

Answer 1

Answer:

Step-by-step explanation:

Let the amount of iron piece be x

Amount of Copper piece=2x

Density of iron=7.8g/cc

Density of copper=8.9g/cc

Weight of iron=7.8x

Weight of copper=17.8x

Total weight=1280g

7.8x+17.8x=1280

25.6x=1280

x=50

Weight of iron=7.8×50=390g

Weight of copper=890g

Volume of iron=390/7.8=50ml

Volume of copper=890/8.9=100ml

Answer 2

Answer:

The volume of iron piece is 50 cc and the volume of copper piece is 100 cc

Step-by-step explanation:

Given:

• The total weight of iron piece and copper piece is 1280 g
• The volume of copper piece is twice that of iron piece.

To find: The volume of iron and copper piece

Solution:

Let the volume of copper  = x .cc

Volume of iron piece = y cc

The volume of copper piece is twice that of the iron piece

             x = 2y

Form the linear equation

1280 = 7.8 y + 8.9 x

8.9 x + 7.8 y = 1280

where x = 2y

Sub x= 2y in the equation

8.9 x + 7.8 y = 1280

8.9 (2y ) + 7.8 y = 1280

17.8 y + 7.8 y = 1280

25.6 y = 1280

  $y = \frac{1280}{25.6}$

y = 50

x = 2y

x = 2 (50)

x = 100

Volume of iron piece = 50 cc

Volume of copper piece = 100 cc

Final answer:

The volume of iron piece is 50 cc and the volume of copper piece is 100 cc

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