Question

The sum of the zeroes of a polynominal 2x^3-3kx^2+4x-5=p(x) is 6...Then find the value of k in the polynomial....

Answer 1

hey mate
here's the solution

Answer 2

Given Equation is 2x^3 - 3kx^2 + 4x - 5.

Here, a = 2, b = -3k, c = 4, d = -5.

Given Sum of zeroes is 6.

Let α,β,∝ are the zeroes of the polynomial.

We know that Sum of zeroes = -b/a

⇒ α + β + ∝ = -(-3k)/2

⇒ 6 = 3k/2

⇒ 12 = 3k

⇒ k = 4.

Therefore, the value of k = 4.

Hope it helps!