the sum of the zeroes of a quadratic polynomial is 15/4 and the product is 3 find the polynomial
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Answered by
15
sum of zero = -b/a
-b/a = 15/4
product of zero = c/a
c/a = 3
a = 4 & b = -15 & c = 3
4x^2-15x +3 is the polynomial
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Answered by
11
Answer:
quadratic polynomial= x^2-(sum of zeroes)+(product of zeroes)
=x^2-15/4+3
= (4x^2-15+12)/4[by taking LCM as 4]
=4x^2-15+12=0×4
=4x^2-15+12
Thus, 4x^2-15+12 is the required polynomial.
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