the sum of the zeroes of a quardatic polynomial 5x2-kx+2 is 7 then find the value of k
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Answered by
1
Step-by-step explanation:
-b/a=7
-b/a=7k/5=7
-b/a=7k/5=7k=35
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Answered by
5
5x²−7x+k=0
Given that roots are reciprocal to each other
Let the roots be x,1/c
Products of roots= k/5 =1
⟹k=5
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