The sum of the zeroes of cubic polynomial
p(x) = 2x3 - 17x2 + 38x - 15 is
of polynomial
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Answer:
Given cubic polynomial is 2x³-17x²+38x-15
Let x = 3
=2(3)³-17(3)²+38(3)-15
=54 - 153 + 114 - 15
=168 - 168
=0
Hence 3 is the zero of the given polynomial.
In the same way,
Let x = 1/2
=2(1/2)³-17(1/2)²+38(1/2)-15
=2(1/8) - 17(1/4) + 19 - 15
= 1/4 - 17/4 + 4
= -16/4 + 4
= -4 + 4
=0
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