Question

The sum of the zeroes of the polynomial 2x^2-8x +6 is
(a) - 3 (b) 3 (c) - 4 (d) 4

Answer 1

Answer:-

Your Answer Is Option (d) 4.

Explanation:-

Given polynomial:-

$\\ \bf\longrightarrow 2 {x}^{2} - 8x + 6.$

To Find:-

• The value of sum of zeroes.

Concept Used:-

In A quadratic polynomial,

▪︎ Sum of Zeroes = $\bf-\dfrac{b}{a}.$

where,

• b = Coefficient of x.

• a = Coefficient of x².

So Here,

• b = -8.

• a = 2.

Therefore,

Sum Of zereos

$\\ \tt= -\dfrac{b}{a}.$

$\\ \tt = -\dfrac{(-8)}{2}.$

$\\ \tt = \dfrac{\cancel{8}}{\cancel{2}}.$

$\\ \huge\red{\boxed{\bf{\blue{ =4.}}}}$

Therefore Sum Of Zeroes Is Equal To 8.

So The Final Answer Is Option (d).

Answer 2

Answer:-

➣

$\bf{Option \: D \: \: 4}$

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• Given:-

$2 {x}^{2} - 8x + 6$

• To Find:-

Value of Sum of Zeroes

• Solution:-

We know that:-

$\bf \boxed{Sum \: of \: Zeroes = \dfrac{-b}{a}}$

here,

$\bf{b} \: is \: Coefficient \: of \: x$

$\bf{a} \: is \: Coefficient \: of \: x^2$

Therefore,

$\bf{b = -8}$

$\bf{a = 2}$

Hence,

Sum Of Zeroes:-

$\implies {\dfrac{-b}{a}}$

$\implies {\dfrac{-(-8)}{2}}$

$\implies{\dfrac{8}{2}}$

$\implies \large{\cancel{\frac{8}{2}}}$

$\\ \large \bf{ =4}$

Hence, Option D

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