Question

the sum of the zeroes of the polynomial 2x² + 3 kx + 3 is 10, the
I the value of k.​

Answer 1

Given

We have given sum of the zeroes of the polynomial 2x²+3kx+3 is 10

To Find

we have to find the value of k

$\sf\huge {\underline{\underline{{Solution}}}}$

Let λ,β & δ be the zeroes of the given polynomial

then ,λ,β + δ

Sum of zeroes = coefficient of x / coefficient of x²

λ+β + δ = -b/a = coefficient of x / coefficient of x²

λ+β + δ = -b/a = - 3k/2

Given sum of zeroes is 10

So, λ+β + δ = -b/a = 10

=> -3k/2= 10

=> 10*2= -3k

=> k= - 20 /3

More information=>

If λ,β & δ are the zeroes then product of zeroes = c/a = constant term / coefficient of x²

Answer 2

$\\{{\fbox{{\fbox{\green{\fbox{\red{ANSWER}}}}}}}}$

Given

We have given sum of the zeroes of the polynomial 2x²+3kx+3 is 10

To Find

we have to find the value of k

Let λ,β & δ be the zeroes of the given polynomial

then ,λ,β + δ

Sum of zeroes = coefficient of x / coefficient of x²

λ+β + δ = -b/a = coefficient of x / coefficient of x²

λ+β + δ = -b/a = - 3k/2

Given sum of zeroes is 10

So, λ+β + δ = -b/a = 10

=> -3k/2= 10

=> 10*2= -3k

=> k= - 20 /3

hope it helps you..