Math, asked by smoked, 7 months ago

The sum of the zeroes of the polynomial 2Y³−3Y²−17Y+30 is​

Answers

Answered by udishakeshariu
2

Answer:

y³ - (2-y³) + (3y²-2y) - (y-4y²)

=y³+2+y³+3y²-2y-y+4y²

=y³+y³+3y²+4y²-2y-y+2

=2y³+7y²-3y+2

Step-by-step explanation:

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Answered by Anonymous
24

Answer:

Eq-> 2y³ - 3y² -17y + 30

a = 2, b= -3, c= -17, d= 30.

Sum of zeroes = -b/a

= - (-3)/2

= 6/2 = 3 ans.

Hope it helps thanks..

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