The sum of the zeroes of the polynomial 2Y³−3Y²−17Y+30 is
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Answered by
2
Answer:
y³ - (2-y³) + (3y²-2y) - (y-4y²)
=y³+2+y³+3y²-2y-y+4y²
=y³+y³+3y²+4y²-2y-y+2
=2y³+7y²-3y+2
Step-by-step explanation:
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Answered by
24
Answer:
Eq-> 2y³ - 3y² -17y + 30
a = 2, b= -3, c= -17, d= 30.
Sum of zeroes = -b/a
= - (-3)/2
= 6/2 = 3 ans.
Hope it helps thanks..
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