Question

the sum of the zeroes of the polynomial f(x)=2x^3-2kx^2+4x-5, find k

Answer 1

Answer:

Sum of the zeros

$= \frac{ - \: coefficient \: of \: {x}^{2} }{coeficient \: of \: {x}^{3} }$

$= \frac{2k}{2}$

$= k$

Sum of the zeros = k

Given sum of zeros = 6

k = 6

Answer 2

❤Answer:

$\frac{ - coefficient \: {x}^{2} }{coeffcient \: of \: {x}^{3} }$

$\frac{2k}{2}$

$k$

Sum of Zero = K

Given sum of zero = 6

So, k = 6