The sum of the zeroes of the polynomial is zero. if one of its zeroes is 3 then find the polynomial
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Answered by
2
Let the two zeros be x,y
A/q..
x+y=0
3+y=0
y=-3
Then,
xy=3(-3)
=-9
The polynomial will be
x^2-(sum of zeros)x+product of zeros
x^2-9
Hope it helps......
Answered by
13
A+B=0
A=3
3+B=0
B= -3
So second zero of polynomial is -3
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