Question

the sum of the zeros of 3 x square - 2 x minus 8 is

Answer 1

Answer:

Step-by-step explanation:

Hey mate

Here is your answer

Answer 2

Answer:

$\bold{\frac{2}{3}}$

Step-by-step explanation:

$3x^2 - 2x - 8 \\ \\ = 3x^2 - 6x + 4x - 8 \\ \\ = 3x\ (x - 2) + 4\ (x - 2) \\ \\ = (x - 2)(3x + 4) \\ \\ \therefore\ x = 2\ \ ;\ \ x = -\frac{4}{3} \\ \\ \\ Sum \ = 2 + (- \frac{4}{3}) = \ 2 - \frac{4}{3} = \frac{6 - 4}{3} = \bold{\frac{2}{3}}$