the sum of the zeros of
![3 {x + 5x}^{2} - 2 3 {x + 5x}^{2} - 2](https://tex.z-dn.net/?f=3+%7Bx+%2B+5x%7D%5E%7B2%7D++-+2)
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Answers
Answered by
1
5x^2+3x-2
sum of zeroes=-b/a
=-3/5
sum of zeroes=-b/a
=-3/5
Answered by
0
Hey!!
p ( x ) = 3x + 5x^2 - 2
p ( x ) = 5x^2 + 3x - 2
Sum of zeroes = - b / a = - 3 / 5 >>>> Answer
Hope it will helps you ✌
p ( x ) = 3x + 5x^2 - 2
p ( x ) = 5x^2 + 3x - 2
Sum of zeroes = - b / a = - 3 / 5 >>>> Answer
Hope it will helps you ✌
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