Question

The sum of the zeros of the polynomial 2x square + 8 x - 2

Answer 1

Proof

There is a polynomial $ax^2+bx+c=0$.

Let there be zeroes $\alpha$ and $\beta$.

Then,

$a(x-\alpha )(x-\beta )=0$.

$ax^2-a(\alpha +\beta )x+a\alpha \beta =ax^2+bx+c$

By the identity,

$-a(\alpha +\beta )=b$.

∴Sum of two zeroes is equal to $-\frac{b}{a}$.

↓ Let's solve the question. ↓

a=2 and b=8, so sum of two zeroes are -4.

∴ -4