Question

The sum of the zeros of the polynomial 3x² + 3x -18 ​

Answer 1

Answer:

the required result is -1.

Step-by-step explanation:

a=3,b=3,c=-18

we know that

sum of the zeroes of the polynomial is -b/a

= -3/3

= -1

Answer 2

Answer:

here

a= 3

b= 3

c= -18

$sum \: of \: the \: zeroes = \frac{ - coefficient \: of \: {x}}{coeeficient \: of \: {x}^{2} } \\ = \frac{ - 3}{3} \\ = - 1$