Question

the sum of the zeros of the polynomial9x^2-5​

Answer 1

Answer:

$9 {x}^{2} - 5 + 0 = 0$

Answer 2

Question:-

The sum of the zeros of the polynomial :-

${9x}^{2} - 5$

Solution:-

sum of the zeros=

$= \frac{ - coefficent \: of \: x}{coefficent \: of \: {x}^{2} } \\ = \frac{ - b}{a} \\ = \frac{ - 0}{9} \\ = 0$

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