Question

the sum of these consecutive multiples of 4 is 36 find these multiples ​

Answer 1

Answer:

Let the 1st no. be 4x then the second no. is equal to 4x+4 and the third is equal to 4x+8

sum of 4x+(4x+4)+(4x+8)=444

12x +12 =444

on solving x=36

Therefore the no.s are 144,148,152

Answer 2

Answer:

16 and 20

Step-by-step explanation:

let these consecutive multiples of 4 be X, X+4

X+X+4=36

2X+4=36

X=32/2

=16 and X+4=16+4=20