Question

The sum of third and last terms of the ap having 4 teams is 14 If the product of the middle Terms is45 find the number
​

Answer 1

first term a=5, last term l=45 and S

n

= 400

Since, S

n

=

2

n

(a+l)

⇒400=

2

n

(5+45)

⇒400=

2

n

(50)

⇒400=n(25)

⇒n=16

Since, l=a+(n-1)d

⇒45=5+(16−1)d

⇒45−5=(15)d

⇒40=15d

⇒d=

15

40

⇒d=

3_

8

Answer 2

Answer:

Thankyou for free points!!!!.......