Question

the sum of third and seventh term of an ap is 6 and their product is 8. find the sum of first 16 terms​

Answer 1

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Answer 2

Answer:

an=a+(n-1)d

so,

A3=a+2d

A7=a+6d

a3+a7=a+2d+a+6d=6

2a+8d=6----1

a3×a7=8

a3= 8/a7-------2

substitute 2 in 1