The sum of thre consecutive number is 126 find the
Sum of first two numbers
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Answered by
0
Three consecutive numbers are x, x 1, and x + 2. 41 + 42 + 43 = 126 for the check.
Answered by
1
Answer:
83
Step-by-step explanation:
Let the three consecutive numbers be x, x+1, x+2..
So according to the question,
x + (x+1) + (x+2) = 126
3x + 3 = 126
3x = 126 - 3
3x = 123
x = 123/3
x = 41
So, the consecutive 3 numbers are:
x = 41
x+1 = 42
x+2 = 43
Therefore, the numbers are 41, 42, 43
In the question they asked the sum of first two numbers,
So, 41 + 42 = 83
Therefore, sum of first two numbers is 83.
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