Question

The sum of three alternate numbers are
3 less than 24. Find the numbers.​

Answer 1

Answer:

The Numbers are - 6,7 and 8.

Step-by-step explanation:

Given :

Sum of 3 consecutive (alternate) numbers = 3 less than 24

To find :

The number

Solution :

Let the number be -

• y
• y + 1
• y + 2

$\bigstar \: \boxed{\sf{y + (y + 1) + (y + 2) = 24 \times 3}}$

$\sf{\implies} \: y + (y + 1) + (y + 2) = 24 - 3 \\ \\ \sf{\implies} \:3y + 3 = 21 \\ \\ \sf{\implies} \:3y = 21 - 3 \\ \\ \sf{\implies} \:3y = 18 \\ \\ \sf{\implies} \:y = \dfrac{18}{3} \\ \\ \sf{\implies} \:y = 6$

One number = 6

$\rule{300}{1.5}$

★ $\textsf{\underline{\underline{Value of (y + 1)}}}$

$\sf{\implies} \:y + 1 \\ \\ \sf{\implies} \:6 + 1 \\ \\ \sf{\implies} \:7$

Second Number = 7

$\rule{300}{1.5}$

★ $\textsf{\underline{\underline{Value of (y + 2)}}}$

$\sf{\implies} \:y + 2 \\ \\ \sf{\implies} \:6 + 2 \\ \\ \sf{\implies} \:8$

Third number = 8

$\therefore$ The Numbers are -

• 6
• 7
• 8

$\rule{300}{1.5}$

$\textbf{\underline{\underline{Verification :}}}$

$\sf{\implies} \:6 + 7 + 8 = 24 - 3 \\ \\ \sf{\implies} \:13 + 8 = 21 \\ \\ \sf{\implies} \:21 = 21$

$\therefore$ The Numbers are - 6,7 and 8.