Question

The sum of three c
Using identity, show that (4pq + 3q)2 – 48pq? = (4pq - 3q)square ​

Answer 1

Answer:

4pq + 3q)² – (4pq – 3q)² = 48pq²

As we know,

(a + b)² = a² + b² + 2ab

and

(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

(4pq + 3q)² – (4pq – 3q)² = L.H.S.

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

= R.H.S.