Question

The sum of three concecutive multipels of 7 is 84.find the 3 multiples

Answer 1

Solution is attached below

Answer 2

$\bf{Here \: is \: the \: answer}$


Let the first number be x
Let the second number be x + 7
Let the third number be x + 14

As per your question,

x + ( x + 7 ) + (x + 14 )= 84

x + x + 7 + x + 14 = 84

3x + 21 = 84

3x = 84-21

3x = 63

x = 21

Thus,
x + 7 = 21 + 7 = 28

x + 14 = 21 + 14 = 35

Thus,
The three consecutive numbers are 21,28,35.

Thanks!!